Gerbil
General information
You start out by finding a suitable problem to solve. Then you write code to solve the problem. After this, you submit the code to us for review. We will then compile your code and run it on some secret input. After some careful deliberation, you will get a judgement informing you whether your code behaved as expected or not.
Input/Output
Your program should read its input from standard input and produce output on standard output.
This can for instance be done using read
/ displayln
.
Input will always follow the input specification (so you do not need to validate the input). Your output must follow the output specification.
Compiler settings
For Gerbil, we use gxc version Gerbil v0.17 on Gambit v4.9.4-180-g266c81f3 with the following flags: -exe -O {mainfile}
.
File Extensions
Files with any of the following file extensions will be used: .ss
System libraries
You are allowed to use all standard libraries included with Gerbil.
Hardware
We are currently using Dell PowerEdge R230 servers for judging. These are equipped with an Intel Xeon E3-1220V6 CPU running at 3.0 GHz and 8 GB RAM. A 64-bit Linux kernel is used.
Exiting
We will inspect the exit code of your program. If it is non-zero, we will judge your submission as Run Time Error.
Solving a problem
Now lets get down to business and write some code. The short tutorial below goes through the solution of A Different Problem.
Step 1: The problem
You are tasked with writing a program that computes the difference between integers. Sounds simple, doesn't it? Well, as we will see, the problem still holds some small difficulties.
Step 2: Reading the input
One thing to note is that the integers can be fairly large, as large as 1015, which is a lot larger than the maximum value of an int (which is 231−1). Luckily, Gerbil supports integers that are arbitrarily large.
Reading is done from standard input. In this problem, we should read until the end of the file (in other problems, there might be an integer at the beginning of the input, specifying how much to read, or there might be a special indicator denoting that there is nothing more to read). Using read, this can be done as below:
Step 3: Computing the answer
Now that we've read the input, it's time to actually solve the problem. Since 0 ≤ a, b ≤ 1015, we have that −(1015) ≤ a−b ≤ 1015, which means that there is no danger of overflow involved in just subtracting the two numbers a and b. Then, we can just take the absolute value by using the builtin abs function.
Finally, it's time to print the result. Using displayln, we can print it as:
Step 4: The solution
Now we are basically done, all that remains is to combine the above parts.
Here is a version of the complete solution.