#### Start

2018-05-21 18:40 UTC

## BSSHS-7th-FINAL

#### End

2018-05-23 19:15 UTC
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# Problem EQuadrant Selection

A common problem in mathematics is to determine which quadrant a given point lies in. There are four quadrants, numbered from $1$ to $4$, as shown in the diagram below: For example, the point $A$, which is at coordinates $(12, 5)$ lies in quadrant $1$ since both its $x$ and $y$ values are positive, and point $B$ lies in quadrant 2 since its $x$ value is negative and its $y$ value is positive.

Your job is to take a point and determine the quadrant it is in. You can assume that neither of the two coordinates will be $0$.

## Input

The first line of input contains the integer $x$ ($-1000 \le x \le 1000; x \not= 0$). The second line of input contains the integer $y$ ($-1000 \le y \le 1000; y \not= 0$).

## Output

Output the quadrant number ($1$, $2$, $3$ or $4$) for the point $(x, y)$.

Sample Input 1 Sample Output 1
10
6

1

Sample Input 2 Sample Output 2
9
-13

4