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Problem Q
Travel Planning

Alice and Bob spend this summer planning next year’s summer vacation. They want to travel from the old city of A-town to the popular summer resort B-ville, but they haven’t yet decided which other places to visit en route. There are $N$ places to visit in total, numbered from $1$ to $N$. A-town is place number $1$ and B-ville is place number $N$. Some places are linked by one-directional connections; a pair of places can be linked by multiple such connections.

Alice and Bob are currently in A-town. Each day they will decide where to travel next by choosing uniformly at random among the connections leaving their current place. Once they reach B-ville, they stop.

Alice and Bob want to book their trip back on a day where they are in B-ville with $95\% $ probability. And they really mean exactly $95\% $ – no more, no less! There is a $10$ day window when train tickets are affordable; if their return trip does no occur within that window they might as well cancel the entire vacation.

You are given a positive integer $L$ and have to find a number $T$ with $L \leq T \leq L + 9$ such that the probability of Alice and Bob being in B-ville after $T$ days is exactly $95\% $. If there is more than one valid $T$, report smallest one.

Input

The first line contains two integers $N$ and $L$, with $2 \leq N \leq 100$ and $1 \leq L \leq 10^6$. The following $N$ lines each contain $N$ integers. The $j$th integer on the $i$th line contains the number $a_{ij}$ of one-directional connections from place $i$ to place $j$, where $0 \leq a_{ij} \leq 10^9$.

There are no connections from a place to itself. No connections leave B-ville (the $N$th place). All other places have at least one outgoing connection, so Alice and Bob will never be stuck.

Output

Print the integer $T$ as described above. If no solution exists, print $-1$.

Sample Input 1 Sample Output 1
3 1
0 11 9
1 0 10
0 0 0
2
Sample Input 2 Sample Output 2
4 3
0 1 0 19
0 0 2 0
0 5 0 3
0 0 0 0
-1
Sample Input 3 Sample Output 3
3 100
0 1 0
1 0 0
0 0 0
-1

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