JMU F17 Week 7

#### Start

2017-10-16 21:00 UTC

## JMU F17 Week 7

#### End

2017-10-23 21:00 UTC
The end is near!
Contest is over.
Not yet started.
Contest is starting in -424 days 12:01:53

168:00:00

#### Time remaining

0:00:00

A common problem in mathematics is to determine which quadrant a given point lies in. There are four quadrants, numbered from $1$ to $4$, as shown in the diagram below:

For example, the point $A$, which is at coordinates $(12, 5)$ lies in quadrant $1$ since both its $x$ and $y$ values are positive, and point $B$ lies in quadrant 2 since its $x$ value is negative and its $y$ value is positive.

Your job is to take a point and determine the quadrant it is in. You can assume that neither of the two coordinates will be $0$.

## Input

The first line of input contains the integer $x$ ($-1000 \le x \le 1000; x \not= 0$). The second line of input contains the integer $y$ ($-1000 \le y \le 1000; y \not= 0$).

## Output

Output the quadrant number ($1$, $2$, $3$ or $4$) for the point $(x, y)$.

Sample Input 1 Sample Output 1
10
6

1

Sample Input 2 Sample Output 2
9
-13

4