# The Bookcase

Wondering how small his bookcase could be, he models the problem as follows. He measures the height $h_ i$ and thickness $t_ i$ of each book $i$ and he seeks a partition of the books in three non-empty sets $S_1,S_2,S_3$ such that $\left(\sum _{j=1}^3 \max _{i \in S_ j} h_ i \right) \cdot \left( \max _{j=1}^3 \sum _{i\in S_ j} t_ i \right)$ is minimized, i.e., the area of the bookcase as seen when standing in front of it (the depth needed is obviously the largest width of all his books, regardless of the partition). Note that this formula does not give the exact area of the bookcase, since the actual shelves cause a small additional height, and the sides cause a small additional width. For simplicity, we will ignore this small discrepancy.

Thinking a moment on the problem, Tom realizes he will need a computer program to do the job.

## Input

The input begins with a line containing a single positive integer $N$, $3\leq N\leq 70$ giving the number of books. Then $N$ lines follow each containing two positive integers $h_ i$, $t_ i$, satisfying $150\leq h_ i \leq 300$ and $5\leq t_ i \leq 30$, the height and thickness of book $i$ respectively, in millimeters.

## Output

Output one line containing the minimum area (height times width) of a three-shelf bookcase capable of holding all the books, expressed in square millimeters.

Sample Input 1 | Sample Output 1 |
---|---|

4 220 29 195 20 200 9 180 30 |
18000 |

Sample Input 2 | Sample Output 2 |
---|---|

6 256 20 255 30 254 15 253 20 252 15 251 9 |
29796 |